Skip to content
  • Start free trial
An original census record

Start a free trial to view

Get access to the original record, as well as a map showing the local area at the time

Household of Alexander Hannay (born 1840, Wigtownshire)

1881 England, Wales & Scotland Census in Whithorn, Wigtownshire, Scotland

Alexander Hannay and 6 other people are on this record


Get access to the original record, as well as a map showing the local area at the time

Alexander Hannay's household

Male

Alexander

Hannay

Head
Female

Jane B

Hannay

Mother
Female

Jane

Hannay

Sister
Female

Elizabeth

Hannay

Sister
Female

Elizabeth

Pettigrew

Servant
Female

Helen

McKenna

Servant
Male

Andrew

Christie

Servant
First name(s) Alexander
Last name Hannay
Relationship Head
Marital status Unmarried
Age 41
Birth year 1840
Birth place Sorbie, Wigtownshire, Scotland

Household members (7 people)

First name(s)

Last name

Relationship

Marital status

Age

Birth year

Birth place

Full record

Alexander

Hannay

Head

Unmarried

41

1840

Sorbie, Wigtownshire, Scotland

Jane B

Hannay

Mother

Widow

69

1812

Kirkinner, Wigtownshire, Scotland

Jane

Hannay

Sister

Unmarried

43

1838

Sorbie, Wigtownshire, Scotland

Elizabeth

Hannay

Sister

Unmarried

33

1848

Sorbie, Wigtownshire, Scotland

Elizabeth

Pettigrew

Servant

Unmarried

18

1863

Sorbie, Wigtownshire, Scotland

Helen

McKenna

Servant

Unmarried

20

1861

Sorbie, Wigtownshire, Scotland

Andrew

Christie

Servant

Unmarried

16

1865

Sorbie, Wigtownshire, Scotland

Explore Findmypast's newspaper collections

Explore the 1881 Census and millions of historical records for free with Findmypast. Find out more about the household of Alexander Hannay in Whithorn in 1881, and follow the Hannay family through time in other national records, newspapers and more.

We've found family trees for Alexander Hannay

We’ve found Alexander Hannay in 63 family trees. Find out more about Alexander Hannay's household and view the Hannay family in family trees created by Findmypast members.

Not who you're looking for?