Skip to content
  • Start free trial
An original census record

Start a free trial to view

Get access to the original record, as well as a map showing the local area at the time

Household of Thomas Lankshear (born 1851, Kent Aydenhard)

1911 Census For England & Wales in Bethnal Green, London,Middlesex

Thomas Lankshear and 7 other people are on this record


Get access to the original record, as well as a map showing the local area at the time

Thomas Lankshear's household

Male

Thomas

Lankshear

Head
Female

Caroline

Lankshear

Wife
Male

Gerald

Lankshear

Son
Male

Frank

Lankshear

Son
Male

Edwin

Lankshear

Son
Female

Lottie

Lankshear

Daughter
Female

Lily

Lankshear

Daughter
Female

Lilian Mary

Lankshear

Grandchild
First name(s) Thomas
Last name Lankshear
Relationship Head
Marital status Married
Age 60
Birth year 1851
Birth place Kent Aydenhard

Household members (8 people)

First name(s)

Last name

Relationship

Marital status

Age

Birth year

Birth place

Full record

Thomas

Lankshear

Head

Married

60

1851

Kent Aydenhard

Caroline

Lankshear

Wife

Married

55

1856

Kent Deptford

Gerald

Lankshear

Son

Single

18

1893

Surrey Bermondsey

Frank

Lankshear

Son

Single

16

1895

Surrey Bermondsey

Edwin

Lankshear

Son

-

11

1900

Surrey Bermondsey

Lottie

Lankshear

Daughter

Single

22

1889

Kent Greenwich

Lily

Lankshear

Daughter

Single

21

1890

Surrey Bermondsey

Lilian Mary

Lankshear

Grandchild

-

3

1908

North East Hackney

Explore Findmypast's newspaper collections

Explore the 1911 Census and millions of historical records for free with Findmypast. Find out more about the household of Thomas Lankshear in Bethnal Green in 1911, and follow the Lankshear family through time in other national records, newspapers and more.

We've found family trees for Thomas Lankshear

We’ve found Thomas Lankshear in 5 family trees. Find out more about Thomas Lankshear's household and view the Lankshear family in family trees created by Findmypast members.

Not who you're looking for?